Answer:
Therefore, the man will use approximately 45.07 Watts of power to carry the 14.0 kg keg box on top of the 1.64 m ladder in 5.00 seconds.
Explanation:
To calculate the power the man will use to carry the keg box on the ladder, we need to determine the work done and the time taken.
Work (W) is calculated by multiplying force (F) by displacement (d), given by the formula:
W = F × d
The force acting on the keg box, considering the weight, is given by:
F = m × g
Where m is the mass of the keg box and g is the acceleration due to gravity (approximately 9.81 m/s^2).
The height (displacement) the keg box is lifted is given as 1.64 m.
Now, let's calculate the power (P) using the formula:
P = W / t
Where t is the time taken, given as 5.00 s.
Let's assume the mass of the keg box is 14.0 kg.
First, we calculate the force (F):
F = m × g
F = 14.0 kg × 9.81 m/s^2
F = 137.34 N
Next, we calculate the work (W):
W = F × d
W = 137.34 N × 1.64 m
W = 225.34 J (Joules)
Finally, we calculate the power (P):
P = W / t
P = 225.34 J / 5.00 s
P ≈ 45.07 W (Watts)
Therefore, the man will use approximately 45.07 Watts of power to carry the 14.0 kg keg box on top of the 1.64 m ladder in 5.00 seconds.