Question

A scuba diver takes a 2.3 L balloon from the surface, where the pressure is 0.90 atm and the temperature is 33 ∘C , to a depth of 25 m , where the pressure is 3.5 atm and the temperature is 13 ∘C .What is the volume of the balloon at this depth

Answer 1

Using the combined gas law formula, we can find the volume of the balloon at a depth of 25 m by converting temperatures to Kelvin and applying the formula. The volume of the balloon at this depth is 0.80 L.

Step-by-step explanation:

To solve this problem, we can use the combined gas law, which relates the initial and final pressures, temperatures, and volumes of a gas.

1. First, we need to convert the temperature from Celsius to Kelvin. To do this, add 273 to the Celsius temperature. 33 °C is equal to 306 K, and 13 °C is equal to 286 K.
2. Next, we can use the combined gas law formula: P1V1 / T1 = P2V2 / T2. We can plug in the known values: (0.90 atm)(2.3 L) / (306 K) = (3.5 atm)(V2) / (286 K).
3. Solving for V2, the volume of the balloon at the depth, we find V2 = (0.90 atm)(2.3 L)(286 K) / (3.5 atm)(306 K) = 0.80 L.

Therefore, the volume of the balloon at a depth of 25 m is 0.80 L.