Final answer:
To prepare 100 mL of 0.13 M C12H22O11 solution, you would need 4.45 grams of sucrose.
Step-by-step explanation:
To calculate the mass of sucrose needed to prepare a certain volume of a solution, we can use the formula:
mass = concentration x volume x molar mass
In this case, the concentration is given as 0.13 M and the volume is 100 mL (which can be converted to L by dividing by 1000), and the molar mass of sucrose is 342.297 g/mol. We can plug in these values to calculate the mass:
mass = 0.13 mol/L x 0.1 L x 342.297 g/mol = 4.45 g