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A 600 lb horse dives into 8 ft of water from 3 meters. A) How long was the horse in the air? B) At what velocity did the horse strike the water? a. A) 0.64 seconds, B) 19.6 m/s b. A) 0.44 seconds, B) 14.2 m/s c. A) 1.28 seconds, B) 39.2 m/s d. A) 0.88 seconds, B) 27.1 m/s

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Final answer:

  • A. The horse was in the air for 0.64 seconds, and
  • The horse was struck the water at a velocity of 19.6 m/s.

The answer is option ⇒ a. A) 0.64 seconds, B) 19.6 m/s

Step-by-step explanation:

A) In order to find out how long the horse was in the air, we can use the equation:

time = √(2 * height / gravity)

time = √(2 * 3 / 9.8)

time = 0.64 seconds

B) To calculate the velocity at which the horse struck the water, we can use the equation:

velocity = √(2 * gravity * height)

velocity = √(2 * 9.8 * 3)

velocity = 19.6 m/s

The answer is option ⇒ a. A) 0.64 seconds, B) 19.6 m/s

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