Question

The Georgian football player is running to kick the ball. He is going with 18 km/h, but he accidentally passes the ball by. So he turns around and goes back with 18 km/h. This happens in 1 minute. What was the player's acceleration during this time? Please provide an answer with an explanation.

Answer 1

The Georgian football player's average acceleration is 1/6 m/s², or about 0.167 m/s², when he changes direction from 5 m/s in one direction to 5 m/s in the opposite direction over the course of 1 minute.

Step-by-step explanation:

When the Georgian football player running at 18 km/h (which is equal to 5 m/s) turns around and goes back with the same speed in 1 minute (or 60 seconds), he effectively makes a change in velocity of 10 m/s (5 m/s forward to 5 m/s in the opposite direction) in this duration. To calculate the average acceleration, we use the formula a = Δv / t, where Δv is the change in velocity and t is the time. In this case, Δv = 10 m/s and t = 60 s.

So the player's average acceleration is:

a = Δv / t

a = 10 m/s / 60 s

a = 1/6 m/s² or approximately 0.167 m/s².