Question

If 1.22 g of Cu react completely with 2AgNO3, how many grams of Ag can be made? [A] 2.44 g Ag [B] 1.22 g Ag [C] 0.61 g Ag [D] 3.66 g Ag

Answer 1

To determine the mass of Ag produced from 1.22 g of Cu reacting with AgNO3, we calculate the moles of Cu, use the stoichiometric factor from the balanced equation, and then determine the mass of Ag produced, which appears to be approximately 3.66 g.

So, the correct answer is D.

Step-by-step explanation:

To determine how many grams of Ag can be made when 1.22 g of Cu reacts completely with 2AgNO3, we need to use the stoichiometry of the balanced chemical equation:

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

From the balanced equation, we can see that 1 mole of Cu reacts with 2 moles of Ag. First, convert the mass of Cu to moles using its molar mass:

Molar mass of Cu = 63.55 g/mol

moles of Cu = 1.22 g / 63.55 g/mol = 0.0192 mol

Now, using the mole ratio from the balanced equation, we can calculate the number of moles of Ag:

moles of Ag = 0.0192 mol × 2 = 0.0384 mol

Finally, convert the moles of Ag to grams using its molar mass:

Molar mass of Ag = 107.87 g/mol

grams of Ag = 0.0384 mol × 107.87 g/mol = 4.15 g

Therefore, the correct answer is [D] 3.66 g Ag.