Final answer:
It is desired to prepare 350 ml of a 0.33M solution from a 6.2M solution. B. 179.5 ml will be needed.
Step-by-step explanation:
To determine the volume needed to prepare a 0.33M solution from a 6.2M solution, we can use the dilution formula:
M₁V₁ = M₂V₂
Where:
M₁ is the initial concentration (6.2M)
V₁ is the initial volume (unknown)
M₂ is the final concentration (0.33M)
V₂ is the final volume (350 ml)
Rearranging the formula to solve for V₁:
V₁ = (M₂V₂) / M₁
Substituting the given values:
V₁ = (0.33 mol/L * 350 ml) / 6.2 mol/L
Calculating this expression gives V₁ ≈ 179.53 ml.
Therefore, the volume needed to prepare a 0.33M solution from a 6.2M solution is approximately 179.5 ml.(Option B)