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First, you must calculate any two x-values. If x=0, then y=2(0)+4=4. You can plot the point (0,4) If x=-2, then y=2(-2)+4=0. You can plot the point (-2,0)

User Stagleton
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The values of the x and y points that are being used in the graph are (0,4) and (-2,0).

Solving a linear algebra equation using the slope-intercept form

The slope-intercept equation can be expressed as y = mx + b. The value of the y-axis can be determined by making x equal to zero. The value of the x-axis can also be determined by making y equal to zero.

Using the general equation:

y = mx + b ;

here:

  • m = slope;
  • b = y-intercept

From the question, we can say our slope is 2, and the y-intercept b = 4. So, our (x,y) values are given as (0,4) and (-2.0).

i.e. when; x = 0

y = 2(0) + 4

y = 0 + 4

y = 4

(x,y) values = (0,4)

when x = -2

y = 2(-2) + 4

y = -4 + 4

y = 0

(x,y) values = (-2,0)

Using the GeoGebra calculator and plotting the points on the graph, we are able to draw a graphical representation of the given slope-intercept equation below.

First, you must calculate any two x-values. If x=0, then y=2(0)+4=4. You can plot-example-1
User Geron
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