Question

An archer stands 60

meters (m) from a target. She launches an arrow, and it lands 3
centimeters (cm) from the bull's-eye. The archer changes her position to 40
m from the target, and her next arrow lands 2
cm from the bull's-eye. She changes her position to 20
m, and her next arrow lands 1
cm from the bull's-eye.

Which points describe the situation when the archer stands at 40
m?

Let the x-
coordinate be the archer's distance from the target in meters, and let the y-
coordinate be the arrow's distance from the bull's-eye in centimeters.

Responses

(40,2)
open paren 40 comma 2 close paren

(60,40)
open paren 60 comma 40 close paren

(2,40)
open paren 2 comma 40 close paren

(40,3)

Answer 1

The point that describes the situation when the archer stands at 40 m is (40, 2)

Which point describe the situation when the archer stands at 40 m?

Represent the archer's distance from the target as x (in meters) and the arrow's distance from the bull's-eye as y (in centimeters).

From the question, the given points are:

• When the archer is at 60 m, the arrow lands 3 cm from the bull's-eye, so the point is (60, 3).
• When the archer is at 40 m, the arrow lands 2 cm from the bull's-eye, so the point is (40, 2).
• When the archer is at 20 m, the arrow lands 1 cm from the bull's-eye, so the point is (20, 1).

Now, if we focus on the points when the archer is at 40 m, we have the point (40, 2).

This implies that the points when the archer stands at 40 m from the target is (40, 2)