Answer:
Yes, f(x) is continuous at x = 0.
Explanation:
To determine if the function f(x) = x^3 + xx is continuous at x = 0, we need to check three conditions:
- The function must be defined at x = 0.
- The limit of the function as x approaches 0 from both the left and the right must exist.
- The value of the function at x = 0 must be equal to the limit.
Let's evaluate these conditions for the given function:
Defined at x = 0:
The function is defined at x = 0 since f(0) = 0^3 + 0 = 0.
Limits as x approaches 0:
lim x→0− f(x) = lim x→0− (x^3 + xx) = lim x→0− x(x^2 + 1) = 0
lim x→0+ f(x) = lim x→0+ (x^3 + xx) = lim x→0+ x(x^2 + 1) = 0
Value of the function at x = 0:
f(0) = 0^3 + 0 = 0.
Since the function is defined at x = 0, the limits from the left and the right are equal, and the value of the function at x = 0 is equal to the limit, we can conclude that the function f(x) = x^3 + xx is continuous at x = 0.