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HELP ME I HAVE TO TEST SOON!!

HELP ME I HAVE TO TEST SOON!!-example-1

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The mean is 6, the variance is 4, and the standard deviation is 2.

How the mean, variance, and standard deviation are computed:

The mean (expected value) of a random variable is the sum of the product of each outcome and its probability.

Mean (μ): μ = Σ [x * P(x)] = 1*(1/21) + 2*(1/21) + 3*(1/21) + 4*(1/21) + 5*(1/21) + 6*(1/21) + 7*(5/7) = 6

The variance is the sum of the squared difference between each outcome and the mean, multiplied by the probability of the outcome.

Variance (σ²): σ² = Σ [(x - μ)² * P(x)] = (1-6)²*(1/21) + (2-6)²*(1/21) + (3-6)²*(1/21) + (4-6)²*(1/21) + (5-6)²*(1/21) + (6-6)²*(1/21) + (7-6)²*(5/7) = 4

The standard deviation is the square root of the variance.

Standard Deviation (σ): σ = √σ² = √4 = 2

Thus, the mean is 6, the variance is 4, and the standard deviation is 2.

Complete Question:

A spinner has the following outcomes and probabilities:

Outcome (x) Probabily P(x)

1 1/21

2 1/21

3 1/21

4 1/21

5 1/21

6 1/21

7 5/7

Compute the mean, variance, and standard deviation.

User Mike Trusov
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