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Y=2/3x-2y=-x+3solve for x and y

User Marius Kohmann
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1 Answer

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21 votes

EXPLANATION

Given the system of equations:

(1) y = 2x/3 - 2

(2) y = -x +3

Substitute y= -x+3

-x + 3 = 2x/3 - 2

Isolate x for -x+3 = 2x/3 - 2

Subtract 3 from both sides:

-x + 3 - 3 = 2x/3 -2 - 3

Simplify:

-x = 2x/3 -5

Subtract 2x/3 from both sides:

-x - 2x/3 = 2x/3 - 5 -2x/3

Simplify:

-5x/3 = -5

Multiply both sides by 3:

3(-5x/3) = 3(-5)

Simplify:

-5x = -15

Divide both sides by -5

-5x/-5 = -15/-5

Simplify:

x = 3

Then, for y = -x + 3

Substitute x = 3

y = -3 + 3

Simplify:

y = 0

The solutions to the system of equations are:

y = 0 , x = 3

User Yaswanth
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