a) The mean weight of the five baby deer is 15.72 pounds. b) The standard deviation of the five baby deer is 0.84 pounds.
How to find mean and standard?
Part a: Find x
To find the mean weight of the five baby deer, add up the weights of the five baby deer and divide by the number of baby deer.
x = (14.5 + 16.8 + 15 + 16.4 + 15.9) / 5
= 78.6 / 5
= 15.72
Therefore, the mean weight of the five baby deer is 15.72 pounds.
Part b: Find s
To find the standard deviation of the five baby deer, calculate the squared deviations from the mean for each baby deer.
(14.5 - 15.72)² = 1.44
(16.8 - 15.72)² = 1.16
(15 - 15.72)² = 0.49
(16.4 - 15.72)² = 0.44
(15.9 - 15.72)² = 0.04
Next, add up the squared deviations from the mean and divide by the number of baby deer.
s² = (1.44 + 1.16 + 0.49 + 0.44 + 0.04) / 5
= 3.57 / 5
= 0.714
Finally, take the square root of the variance to find the standard deviation.
s = √0.714 = 0.84
Therefore, the standard deviation of the five baby deer is 0.84 pounds.
Complete question:
The mean weight of baby deer and a local zoo is 15.8 pounds with a standard deviation of 2.4 pounds a researcher records the weight of the following five baby deer 14.5 pounds 16.8 pounds 15 pounds 16.4 pounds and 15.9 pounds a. Find x b. Find s