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There are 60 terms of ap of which the first term is 8 and last tem is 185 the 31st term is

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The 31st term of the arithmetic progression is 98.

The Breakdown

The formula for the nth term of an AP is given by:

an = a1 + (n - 1) × d

Where:

an = nth term of the AP

a1 = first term of the AP

n = position of the term in the AP

d = common difference between consecutive terms

Given that the first term (a1) is 8 and the last term (an) is 185, we can find the common difference (d) using the formula:

an = a1 + (n - 1) × d

185 = 8 + (60 - 1) × d

185 = 8 + 59d

177 = 59d

d = 177 / 59

d = 3

Now that we have the common difference (d), we can find the 31st term (a31) using the formula:

a31 = a1 + (31 - 1) × d

a31 = 8 + 30 × 3

a31 = 8 + 90

a31 = 98

Therefore, the 31st term of the arithmetic progression is 98.

User Ian Graham
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