The mass of HF produced by the reaction of 1.2 x 10²⁴ molecules of H₂ with excess F₂ is 79.74 grams.
To solve this problem
Given that we have 1.2 x 10²⁴ molecules of H₂, we can use Avogadro's number (6.022 x 10²³ molecules/mol) to convert the number of molecules to moles:
1.2 x 10²⁴ molecules H₂ × (1 mol H₂ / 6.022 x 10²³ molecules H₂) = 1.99 mol H₂
Second, let's connect moles of
to moles of HF using the stoichiometry.
Since the stoichiometry of the reaction is 1 molecule of H₂F₂ to 2 molecules of HF, we can say that:
1 molecule of H₂F₂ → 2 moles of HF
Therefore, 1.99 mol H₂ × (2 mol HF / 1 mol H₂F₂) = 3.98 mol HF
Now, To convert moles of HF to grams, we need to use the molar mass of HF, which is 20.01 g/mol.
3.98 mol HF × (20.01 g HF / 1 mol HF) = 79.74 g HF
So, the mass of HF produced by the reaction of 1.2 x 10²⁴ molecules of H₂ with excess F₂ is 79.74 grams.