Question

Sunita is x years old Beth is one year younger than sunita joel is double Sunitas age the mean if their ages is 5 how old is Joel

Answer 1

Sunita is x years old

Beth is one year younger than Sunita= x-1

Joel is twice Sunita's age = 2x

their average age is 5

(x+x-1+2x)/3 =5

(4x-1)/3=5

4x-1=3*5

4x-1=15

4x=15+1

x= 4

Sunita is 4 years old, Joel is twice Sunita's age, i.e. 8 years old.

Answer 2

To find Joel's age, set up an equation using the mean of their ages. Solve the equation to find x, and then find Joel's age.

Step-by-step explanation:

To find Joel's age, we need to represent the ages of Sunita, Beth, and Joel in terms of x. Let's say Sunita's age is x years. Beth is one year younger than Sunita, so Beth's age is (x - 1) years. Joel is double Sunita's age, so Joel's age is 2x years.

The mean of their ages is 5, so we can set up the equation (x + (x - 1) + 2x)/3 = 5. Simplifying this equation, we get 4x - 1 = 15. Solving for x, we find that x = 4.

Since Joel's age is 2x, Joel's age is 2(4) = 8 years.