Question

How am I supposed to do this? I would understand if both coefficients were the same variable, but I really don't know what to do when there are two different variable coefficients.

Answer 1

-14

Explanation:

Meaning at x = 1 → ax³ - 6x = bx² +4.... [1]

d(ax³ - 6x)/dx = d(bx² + 4)/dx ... [2]

[1]

ax³ - 6x = bx² +4

a(1)³ - 6(1) = b(1)² + 4

a - 6 = b + 4

b = a - 10 ... [1a]

[2]

d(ax³ - 6x)/dx = d(bx² + 4)/dx

3ax² - 6 = 2bx

3a(1)² - 6 = 2b(1)

3a - 6 = 2b ← substitute b with [1a]

3a - 6 = 2(a - 10)

a = -14