Answer:
![1.58\ \text{g}](https://img.qammunity.org/2022/formulas/chemistry/college/95zdju0pfw77b8fof96ljdb4s277g2hbut.png)
Step-by-step explanation:
10.11 g sample of
contains 22.34%
by mass
According to the law of constant composition the if one sample of
has 22.34% of
by mass then any other sample of
will have the same percentage of the amount of
.
For a sample of 7.09 g we have
![7.09* (22.34)/(100)=1.583906\approx 1.58\ \text{g}](https://img.qammunity.org/2022/formulas/chemistry/college/lch398id88yd9ypzqh0jskncdz05gr18d9.png)
The mass of sodium in the required sample is
.