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2 votes
Evaluate b - 2 a - c for a = -3, b = 9, and c = -6.

2 Answers

4 votes

Answer:

21

Explanation:

Since the value of a , b and c are already given ,

we can input these values in the equation b - 2a -c

A/Q , a = -3 , b = 9 , c = -6

∴ b - 2a - c

= ( 9 ) - 2×( -3 ) - ( -6 ) [ Note : ( - ) × ( - ) = + ]

= 9 + 6 + 6

= 21

User Kazuhiro
by
8.8k points
4 votes

Answer:

21

Explanation:

To evaluate the expression
\sf b - 2a - c for the given values of
\sf a = -3,
\sf b = 9, and
\sf c = -6, substitute these values into the expression:


\sf b - 2a - c


\sf = 9 - 2(-3) - (-6)


\sf = 9 + 6 + 6


\sf = 21

So,
\sf b - 2a - c is equal to 21 when
\sf a = -3,
\sf b = 9, and
\sf c = -6.

User Catalina
by
8.0k points

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