In the figure, angle B is 92 deg 57'
How to solve for angle B
Angle B in the figure is solved using the concept of sine rule
Applying sine rule we have the proportion
Sine A / 13.375 = sine 27deg 10' / 7.060
sine A = 13.375 * 7.060 / sine 27 deg 10'
sine A = 0.86498
A = arcsin (0.86498) = 59.88
angle A + angle B + angle C = 180 (sum of angles of a triangle)
59.88 + angle B + 27 deg 10' = 180
angle B = 180 - 27 deg 10' - 59.88
angle B = 92 deg 57'