Question

Emma has some dimes and some quarters. She has a minimum of 15 coins worth no more than $2.85 combined. If Emma has 6 quarters, determine all possible values for the number of dimes that she could have.

Answer 1

Emma has 6 dimes and 6 quarters.

Explanation:

Let D and Q stand for the number of Dimes and Quarters, respectively.

We learn that D + Q >= 15

Also that $0.1D + $0.25Q = $2.85 [Each D is worth $0.1 and each Q is $0.25]

We are told that Q = 6

Since D + Q >= 15 and Q = 6, D + 6 >= 15

D >= 9

0.1D + 0.25Q = $2.85

0.1D + 0.25(9) = $2.85

0.1D + $2.25 = $2.85

0.1D = $0.60

D = 6

Emma has 6 dimes and 6 quarters.