Question

A chemist prepares a solution of potassium permanganate (KMnO4) by measuring out 0.67 μmol of potassium

permanganate into a 300. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in μmol/L of the chemist's potassium permanganate solution. Round your answer to 2 significa
digits.
?

Answer 1

calculate the concentration of the potassium permanganate solution, we need to divide the number of moles (0.67 μmol) by the volume of the solution (300 mL). Let's convert the volume to liters first by dividing it by 1000:

300 mL ÷ 1000 = 0.3 L

Now we can calculate the concentration:

Concentration = moles/volume

Concentration = 0.67 μmol / 0.3 L

Concentration ≈ 2.23 μmol/L

So, the concentration of the chemist's potassium permanganate solution is approximately 2.23 μmol/L