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What is the equation of the blue line Worth 15 points

What is the equation of the blue line Worth 15 points-example-1

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Answer:

y = -3x -1

Step-by-step explanation:

To find equation first find slope:


\sf slope = (y_2 - y_1)/(x_2 - x_1) where (x1, y1) and (x2, y2) are points

Take two points which the line cross through: (0, -1), (1, -4)


\sf slope = (-4-(-1))/(1-0) = (-4+1)/(1) = (-3)/(1) =-3

Now find equation:

y - y1 = m(x - x1) where m is the slope

y -(-1) = -3(x - 0)

y + 1 = -3x

y = -3x -1

User Felwithe
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