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Find the coefficient of X and X^2 term in (x-3)(x+5)

User Dan Getz
by
7.6k points

2 Answers

1 vote

Answer:

The coefficient of
\sf x term :
\sf 2

The coefficient of
\sf x^2 term :
\sf 1

Explanation:

To find the coefficients of
\sf x and
\sf x^2 in the product
\sf (x - 3)(x + 5), let's first perform the multiplication:


\sf (x - 3)(x + 5) = x(x + 5) - 3(x + 5)

Now, distribute the terms:


\sf = x^2 + 5x - 3x - 15

Combine like terms:


\sf = x^2 + 2x - 15

Now, we can identify the coefficients:

  • The coefficient of
    \sf x term is
    \sf 2.
  • The coefficient of
    \sf x^2 term is
    \sf 1.

Therefore, in the expression
\sf (x - 3)(x + 5), the coefficient of the
\sf x term is
\sf 2 and the coefficient of the
\sf x^2 term is
\sf 1.

User Kirschkern
by
8.0k points
2 votes

Answer:

Coefficient of x^2 is 1 and x is 2

Given equation:

(x-3)(x+5)

Distribute:

(x)(x) + 5(x) -3(x) -3(5)

evaluate:

x² + 5x -3x -15

simplify:

x² + 2x -15

1x² + 2x - 15

Here the coefficient of x^2 is 1 and x is 2 and constant -15.

User Erik Bergsten
by
8.3k points