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Express the series (-6a - 3a + 0 + 3a + 6a) using sigma notation. a) (sum_{n=1}^{5}na) b) (sum_{n=1}^{5}(-3 + 3n)a) c) (sum_{n=1}^{5}(-6 + 3n)a) d) None of the above

User Jreikes
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Answer:

To express the series (-6a - 3a + 0 + 3a + 6a) using sigma notation, we can observe that the terms follow a pattern. The terms are multiples of 'a' with coefficients that change based on the position in the series.

The series can be written as:

(sum_{n=1}^{5}(3n-9)a)

Therefore, the correct answer is c) (sum_{n=1}^{5}(-6 + 3n)a).

User Remco Te Wierik
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