Answer:
To express the series (-6a - 3a + 0 + 3a + 6a) using sigma notation, we can observe that the terms follow a pattern. The terms are multiples of 'a' with coefficients that change based on the position in the series.
The series can be written as:
(sum_{n=1}^{5}(3n-9)a)
Therefore, the correct answer is c) (sum_{n=1}^{5}(-6 + 3n)a).