Final answer:
The two airplanes will be at the same altitude after 6 minutes, and that altitude will be 15,600 feet.
Step-by-step explanation:
To determine when two airplanes will be at the same altitude, we can set up a linear equation for each airplane's altitude over time, where t represents the time in minutes after the first plane starts descending.
- The descending airplane's altitude as a function of time: A(t) = 36,600 - 3,500t
- The ascending airplane starts at the ground level: B(t) = 2,600t
We will find a common value of t where A(t) = B(t).
Setting the two equations equal to each other gives us:
36,600 - 3,500t = 2,600t
Now, combining like terms:
36,600 = 3,500t + 2,600t
36,600 = 6,100t
Dividing both sides by 6,100 gives us:
t = 6
Now that we know t, we can find the altitude at that time for either airplane:
A(6) = 36,600 - 3,500 * 6 = 36,600 - 21,000 = 15,600 feet
Therefore, they will be at 15,600 feet altitude in 6 minutes.