Final answer:
The student inquires about the value measured at a point given a velocity field v = 3i+2j-4k. The value of interest is the magnitude of this velocity vector, which is calculated to be approximately 5.39 units.
Step-by-step explanation:
The student is asking about a specific velocity field given as v = 3i+2j-4k, and they want to know the value of what is measured at the point in three-dimensional space.
Since the velocity vector is already given and there's no clear mention of what specific additional value needs to be found (such as acceleration, force, or another quantity) at the point where the measurement is taken, we assume the student refers to finding the magnitude of the velocity vector.
To find this, we utilize the formula for the magnitude of a vector which is the square root of the sum of the squares of its components.
The magnitude |v| can be calculated as:
- |v| = √(3^2 + 2^2 + (-4)^2)
- |v| = √(9 + 4 + 16)
- |v| = √29
- |v| ≈ 5.39 units (assuming the units are consistent)
The magnitude of the velocity vector at the point in space is approximately 5.39 units.