Question

A cart of mass (8.4kg) is moving in a circular path of radius (2.0m), a centripetal force of (42N) is applied to the cart. What is the tangential velocity of the cart?

Answer 1

To find the tangential velocity of the cart, we can use the formula for centripetal force:

F = (m * v^2) / r

Where:

F = centripetal force

m = mass

v = tangential velocity

r = radius of the circular path

We can rearrange the formula to solve for the tangential velocity:

v = sqrt((F * r) / m)

Plugging in the values:

F = 42N

r = 2.0m

m = 8.4kg

v = sqrt((42 * 2) / 8.4)

v = sqrt(84 / 8.4)

v = sqrt(10)

v ≈ 3.16 m/s

So, the tangential velocity of the cart is approximately 3.16 m/s.