Answer:
Explanation:
(2)
x + y = 2
x = 2 - y
substitute x = (2-y) into (1)
(1)
x² + y² = 34
(2-y)² + y² = 34
4 - 4y + y² + y² = 34
2y² - 4y + 4 - 34 = 0
2y² - 4y - 30 = 0
y² - 2y - 15 = 0
(y-5)(y+3) = 0
y₁ = 5
y₂ = -3
substitute y₁ & y₂ into (2)
x₁ + y₁ = 2
x₁ + 5 = 2
x₁ = -3
x₂ + y₂ = 2
x₂ - 3 = 2
x₂ = 5