Question

Pis a point on they - axis with - 5 as ordinate and Q(4, 3) is

the other point. Find the length PQ

Answer 1

PQ ≈ 8.9 units

Explanation:

calculate the length of PQ using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

given P has ordinate of - 5 and is on the y- axis, then coordinates of P are

P (0, - 5 )

let (x₁, y₁ ) = P (0, - 5 ) and (x₂, y₂ ) = Q (4, 3 )

substitute these values into the formula for d

d =
`√((4-0)^2+(3-(-5))^2)`

=
`√(4^2+(3+5)^2)`

=
`√(16+8^2)`

=
`√(16+64)`

=
`√(80)`

≈ 8.9 units ( to the nearest tenth )