\[ V_s^2 = V_0^2 + 2a s \]
Given:
- Initial velocity (\(V_0\)) is 0 m/s.
- Final velocity (\(V_s\)) is 25 m/s.
- Acceleration (\(a\)) is 3.5 m/s².
Plug in these values into the equation:
\[ 25^2 = 0^2 + 2 \times 3.5 \times s \]
\[ V_s^2 = V_0^2 + 2a s \]
Given:
- \(V_0 = 0 \, \text{m/s}\)
- \(V_s = 25 \, \text{m/s}\)
- \(a = 3.5 \, \text{m/s}^2\)
\[ 25^2 = 0^2 + 2 \times 3.5 \times s \]
\[ 625 = 7s \]
Now, solve for \(s\):
\[ s = \frac{625}{7} \]
Therefore, the displacement (\(s\)) is approximately \(89.29 \, \text{meters}\).