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What will be the final temperature of a 10.0 g piece of iron (Cs = 0.449 J/(g.°C)) initially at 25.0 °C, if it is supplied with 9.50 J from a stove?

User BenFire
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1 Answer

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Answer:

To find the final temperature of the iron piece, we can use the equation:

q = m * Cs * ΔT

Where:

q is the heat energy transferred to the iron piece (9.50 J in this case),

m is the mass of the iron piece (10.0 g),

Cs is the specific heat capacity of iron (0.449 J/(g.°C)),

ΔT is the change in temperature.

Rearranging the equation, we can solve for ΔT:

ΔT = q / (m * Cs)

Substituting the given values:

ΔT = 9.50 J / (10.0 g * 0.449 J/(g.°C))

Calculating the value:

ΔT = 21.38 °C

To find the final temperature, we add the change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT

Final temperature = 25.0 °C + 21.38 °C

Final temperature = 46.38 °C

Therefore, the final temperature of the iron piece will be approximately 46.38 °C.

User Ravjit Singh
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