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moles of cobalt(ii) chloride hexahydrate given the starting solution had a concentration of 1.25 m, how many moles of co[h2o]6cl2 were available in the amount of starting solution you used? unrounded rounded moles of co[h2o]6cl2 (mol)

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a) The molar mass of trans-[Co(en)2Cl2]Cl is 299.42 g/mol and there were 0.0096375 moles available in the starting solution. b) The theoretical yield of the product is 2.8843 grams. c) The percent yield of the product is 42.21%.

a) The molar mass of trans-[Co(en)2Cl2]Cl is calculated by summing the atomic masses of all the atoms in the compound. The atomic masses are as follows: Co = 58.93 g/mol, en = 59.07 g/mol, Cl = 35.45 g/mol. Therefore, the molar mass of trans-[Co(en)2Cl2]Cl is 58.93 + 2(59.07) + 2(35.45) + 35.45 = 299.42 g/mol. The number of moles available in the starting solution can be calculated using the formula: moles = volume (in liters) × molarity. Converting the volume from milliliters to liters and substituting the values into the formula gives: moles = 7.71 mL / 1000 mL/L × 1.25 mol/L = 0.0096375 mol.

b) The theoretical yield of the product can be calculated using the formula: theoretical yield (in grams) = moles of product × molar mass of product. The number of moles of product is 0.0096375 mol. Substituting the molar mass of trans-[Co(en)2Cl2]Cl from part a into the formula gives: theoretical yield = 0.0096375 mol × 299.42 g/mol = 2.8843 g.

c) The percent yield of the product can be calculated using the formula: percent yield = (actual yield / theoretical yield) × 100. Substituting the values into the formula gives: percent yield = (1.217 g / 2.8843 g) × 100 = 42.21%.

The complete question is- 7.71 mL of Co[H2O]6Cl2 of a 1.25 M cobalt(II)chloride hexahydrate was used to begin the synthesis. Volume of Co[H20]6Cl2: 7.71mL a)What is the molar mass of trans-[Co(en)2Cl2]Cl and how many moles were available in the amount of starting solution? b)What is the theoretical yield of product in grams? c) Based on the theoretical yield and the obtained

7.71 mL of Co[H2O]6Cl2 of a 1.25 M cobalt(II)chloride hexahydrate was used to begin the synthesis.

Volume of Co[H20]6Cl2: 7.71mL

a)What is the molar mass of trans-[Co(en)2Cl2]Cl and how many moles were available in the amount of starting solution?

b)What is the theoretical yield of product in grams?

c) Based on the theoretical yield and the obtained mass product(1.217g), what is the percent yield of product, trans-[Co(en)2Cl2]Cl?

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