105k views
1 vote
in 2000, 5% of all light vehicles sold in the united states were pickups and 35% were passenger cars. moreover, a randomly chosen vehicle sold that year was twice as likely to be an suv as a minivan. find the associated probability distribution.

User Tony Adams
by
7.6k points

1 Answer

3 votes

Answer:

To find the associated probability distribution, we need to determine the probabilities for each category of vehicles: pickups, passenger cars, SUVs, and minivans.

Given the information provided:

- 5% of all light vehicles sold were pickups, so the probability of selecting a pickup is 0.05.

- 35% of all light vehicles sold were passenger cars, so the probability of selecting a passenger car is 0.35.

- A randomly chosen vehicle sold in 2000 was twice as likely to be an SUV as a minivan. Let's denote the probability of selecting a minivan as "x". Therefore, the probability of selecting an SUV is 2x.

Since the sum of all probabilities should equal 1, we can set up an equation:

0.05 + 0.35 + 2x + x = 1

Combining like terms:

3x + 0.4 = 1

Subtracting 0.4 from both sides:

3x = 0.6

Dividing both sides by 3:

x = 0.2

Now we can determine the probabilities for each category:

- Probability of selecting a pickup: 0.05

- Probability of selecting a passenger car: 0.35

- Probability of selecting an SUV: 2x = 2(0.2) = 0.4

- Probability of selecting a minivan: x = 0.2

Therefore, the associated probability distribution is as follows:

Pickup: 0.05

Passenger Car: 0.35

SUV: 0.4

Minivan: 0.2

User Z Li
by
7.2k points