The value of the ratio m₁/m₂ is 0.35.
The acceleration of the combined object under the action of the force F is approximately 1.037 m/s².
How to find ratio and acceleration?
(a) Use Newton's second law:
![\[ F = m \cdot a \]](https://img.qammunity.org/2024/formulas/physics/high-school/pl3c77v13p8vxnixg5jyp875bz6xjmaxrh.png)
For the first object with mass m₁ and acceleration a₁:
![\[ F = m_1 \cdot 4.00 \]](https://img.qammunity.org/2024/formulas/physics/high-school/bae1f5f2bisrv8sh6mqrhpyqdjoui65qvc.png)
For the second object with mass m₂ and acceleration a₂:
![\[ F = m_2 \cdot 1.40 \]](https://img.qammunity.org/2024/formulas/physics/high-school/dpn1pn47z3q0odp45y5wvl2r2rl9iptvv2.png)
Since the same force F is applied in both cases, set the equations equal to each other and solve for the ratio
:
![\[ m_1 \cdot 4.00 = m_2 \cdot 1.40 \]](https://img.qammunity.org/2024/formulas/physics/high-school/kvefpia60ogri3drngw6x7b9z8ws6bdolh.png)
![\[ (m_1)/(m_2) = (1.40)/(4.00) \]](https://img.qammunity.org/2024/formulas/physics/high-school/gez2o1xkvtm09ar0sfookmalxa3ow8e998.png)
![\[ (m_1)/(m_2) = 0.35 \]](https://img.qammunity.org/2024/formulas/physics/high-school/1jvr31ogapu9jpgh7rpv1b3dredhwgl20t.png)
(b) When masses m₁ and m₂ are combined, the total mass
is m₁ + m₂. The same force F applied to the combined mass will produce a new acceleration
.
Using Newton's second law again:
![\[ F = m_{\text{total}} \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/v8ne9l8qwyow5pziqklvcucubxbns1nwd3.png)
, so:
![\[ m_1 \cdot 4.00 = (m_1 + m_2) \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/7sb667ou86jywxan3v911ac2n8apv00fbr.png)
Now, using the ratio
to express m₂ in terms of m₁:
![\[ m_2 = (m_1)/(0.35) \]](https://img.qammunity.org/2024/formulas/physics/high-school/5ad8t86uxkz0uyn3913ljatxyw22pcb6sr.png)
Substitute m₂ back into the equation:
![\[ m_1 \cdot 4.00 = \left(m_1 + (m_1)/(0.35)\right) \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/q47xl93zw55hc57y5p825wo9ic2ywvqcvh.png)
![\[ 4.00 = \left(1 + (1)/(0.35)\right) \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/9iq5ffbu04n5bxo5cl0urq7un6t6oe2rd4.png)
![\[ 4.00 = \left(1 + (1)/(0.35)\right) \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/9iq5ffbu04n5bxo5cl0urq7un6t6oe2rd4.png)
![\[ 4.00 = \left(1 + 2.8571\right) \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/8o7s6kggx5jm7uwwnskji8mmkmpumye98u.png)
![\[ 4.00 = 3.8571 \cdot a_{\text{total}} \]](https://img.qammunity.org/2024/formulas/physics/high-school/5ep2uzte1ah9tpmwv9xo6s5ixs0e6pfrop.png)
![\[ a_{\text{total}} = (4.00)/(3.8571) \]](https://img.qammunity.org/2024/formulas/physics/high-school/mvlpvwcdfwcua0f3yvagwiixv0cnkdus4g.png)
![\[ a_{\text{total}} \approx 1.037 \text{ m/s}^2 \]](https://img.qammunity.org/2024/formulas/physics/high-school/aivm4wa420lgc0v9kvryw1og75bc8f4qun.png)
The acceleration of the combined object under the action of the force F is approximately 1.037 m/s².