The molarity of the nickel left in the solution is 0.126 M.
We can see that the net ionic equation is;

Number of moles of nickel solution = 260/1000 L * 0.230 M
= 0.0598 moles
Number of moles of hydroxide solution = 120/1000 L * 0.2 M
= 0.024 moles
If 1 mole of nickel solution reacts with 2 moles of hydroxide
x moles of nickel reacts with 0.024 moles of hydroxide
x = 0.012 moles
Moles of nickel left = 0.0598 moles - 0.012 moles
= 0.0478 moles
Molarity of the nickel left in solution = 0.0478 moles/(120 + 260)/1000 L
= 0.126 M