Question

A circular disk with moment of inertia 1 2 m R² , mass m and radius R is mounted at its center, about which it can rotate freely. A light cord wrapped around it supports a weight m g. R I ω m T g Find the total kinetic energy of the system when the weight is moving at a speed v.

Answer 1

(3/4) mv^2

Step-by-step explanation:

KE total = KE rotational + KEm

= (1/2) mv^2 + (1/2) I w^2

= (1/2) mv^2 + (1/2) * (1/2) r^2 m (v/r)^2

= (3/4) mv^2