Question

P(x) = 2x^{3}-9x^{2}+9x-20
what is the remainder when it is divided by (x-4)

Answer 1

The remainder is 0.

Explanation:

I am assuming this is the equation:

`p(x)=2x^3-9x^2+9x-20`

If this equation is incorrect, let me know and I will fix my answer.

According to the Remainder Theorem, the remainder of
`(p(x))/((x-a))` is
`p(a)`. In other words, you just have to evaluate
`p(4)`.

`p(4)=2(4)^3-9(4)^2+9(4)-20=0`

The remainder is 0.

You can divide the polynomial using long division or synthetic division and you will get a remainder of 0 since 4 is a root of the equation.