Question

Please help someone i don't know

Answer 1

`\sf \tan x = (15 √(97))/(97)`

Explanation:

The tangent identity is given by:

`\sf \tan x = (\sin x)/(\cos x)`

Given that
`\sf \sin x = (15)/(17)` and
`\sf \cos x = (√(97))/(17)`, we can substitute these values into the formula:

`\sf \tan x = ((15)/(17))/((√(97))/(17))`

To simplify, multiply the numerator and denominator by the conjugate of the denominator (which is
`\sf (√(97))/(17)`):

`\sf \tan x = (15)/(17) * (17)/(√(97))`

Cancel out the common factor of 17:

`\sf \tan x = (15)/(√(97))`

To rationalize the denominator, multiply the numerator and denominator by
`\sf √(97)`:

`\sf \tan x = (15 √(97))/(97)`

So,
`\sf \tan x = (15 √(97))/(97)`.