Question

`3x^2+x-5=0`

Answer 1

The two solutions for the quadratic equation are:

x = -1.47

x = 1.13

How to solve the quadratic equation?

Here we have the quadratic equation:

3x² + x- 5 = 0

Remember that for the general quadratic equation:

ax² + bx + c = 0

The solutions are given by:

`x = (-b \pm √(b^2 - 4ac) )/(2a)`

In this case:

a = 3

b = 1

c = -5

Then the solutions are:

`x = (-1 \pm √(1^2 - 4*3*-5) )/(2*3) \\\\x= (-1 \pm 7.8 )/(6)`

Then the two solutions are:

x = (-1 - 7.8)/6 = -1.47

x = (-1 + 7.8)/2 = 1.13

Complete question:

"Solve the quadratic equation:

3x² + x- 5 = 0"