Question

If the two roots of the quadratic equation : k X²-2 kx + 3 = 0 are equal real roots , then k =​

Answer 1

Answer:
`k = 3`

Reason

When the two roots are equal real roots, aka double roots, the discriminant is 0.

`d = 0\\\\b^2 - 4ac = 0\\\\(-2k)^2 - 4(k)(3) = 0\\\\4k^2 - 12k = 0\\\\4k(k - 3) = 0\\\\4k = 0 \ \text{ or } \ k-3 = 0\\\\k = 0 \ \text{ or } \ k = 3\\\\`

If
`k = 0`, then
`k\text{x}^2 - 2k\text{x} + 3 = 0` reduces to
`3 = 0`. This is a contradiction.

So we'll ignore that solution and focus on k = 3 as the only answer.