213k views
4 votes
What is the probability of 5 broken Hard Drives (HD) out of 190 sampled HD in number of trials?

User Tbenst
by
7.4k points

1 Answer

3 votes

Final answer:

The probability of 5 broken Hard Drives (HD) out of 190 sampled HD in a number of trials can be calculated using the binomial probability formula. After calculating the values, the probability is approximately 0.0106.

Step-by-step explanation:

The probability of 5 broken Hard Drives (HD) out of 190 sampled HD in a number of trials can be calculated using the binomial probability formula. The formula is:

P(X=k) = (nCk) * p^k * (1-p)^(n-k)

Where:

  • P(X=k) is the probability of getting k successes (in this case, 5 broken HDs)
  • n is the number of trials (in this case, 190)
  • p is the probability of success in a single trial (broken HD)

Let's assume the probability of a single HD being broken is 0.1. Using the formula:

P(X=5) = (190C5) * 0.1^5 * (1-0.1)^(190-5)

After calculating the values, the probability is approximately 0.0106.

Learn more about probability of broken Hard Drives in a sample

User Krazykrejza
by
7.7k points