Question

If Tom kicks a 0.350 kg soccer ball with 0.90 N of force, what is the acceleration of the ball? F= ma 0.32 m/s² 3.15 m/s² 388.9 m/s² 2.6 m/s² 315 m/s² 0.003 m/s²​

Answer 1

d) 2.6 m/s^2

Step-by-step explanation:

We are given:

m = 0.350 kg

F = 0.90 N

With the equation of F = ma, we can rearrange it to have acceleration by itself on one side:

F = ma

F/m = a

Now, let's plug in what we know and solve for a:

a = F/m

a = (0.90 N) / (0.350 kg)

a = 2.6 m/s^2

Thus, the acceleration of the ball is 2.6 m/s^2 which is option d.

Hope this helps :)