In the figure, the values of x and y ae
x = 5 inches
y = 16 inches
How to find the values of x and y
From the area of triangle ABC, we solve for y
Area, A = 0.5 base * height
where
base = y
height = 2.5
A = 20 square inches
plugging in the values
20 = 0.5 (y) * 2.5
40 = 2.5(y)
y = 40/2.5
y = 16 inches
To find x, we will require angle C. We find angle C using trigonometry for the right triangle BEC
sine C = opposite / hypotenuse
sine C = 2.5 / 8
C = arcsin (2.5/8) = 18.21
Using right triangle ADC, now y = 16 inches is the hypotenuse
sine C = x/y
2.5/8 = x / 16
x = (16 * 2.5) / 8
x = 5 inches