Question

How many moles of AIN in 34.8g?
Please show work or explanation

Answer 1

To determine the number of moles (\(n\)) in a given mass of a substance, you can use the formula:

Step-by-step explanation:

\[ n = \frac{\text{mass}}{\text{molar mass}} \]

For aluminum nitride (\(AlN\)), you need to find the molar mass of \(AlN\) by summing the atomic masses of its constituent elements (aluminum and nitrogen).

1. **Find the Atomic Masses:**

- Aluminum (\(Al\)) has an atomic mass of approximately 27 g/mol.

- Nitrogen (\(N\)) has an atomic mass of approximately 14 g/mol.

2. **Calculate the Molar Mass of \(AlN\):**

\[ \text{Molar mass of } AlN = (\text{Number of Al atoms} \times \text{Atomic mass of Al}) + (\text{Number of N atoms} \times \text{Atomic mass of N}) \]

\[ \text{Molar mass of } AlN = (1 \times 27) + (1 \times 14) \]

3. **Calculate the Number of Moles (\(n\)):**

\[ n = \frac{\text{mass}}{\text{molar mass of } AlN} \]

\[ n = \frac{34.8}{27 + 14} \]

Now, calculate \(n\) to find the number of moles of \(AlN\) in 34.8g.

Answer 2

0.848 moles

Step-by-step explanation:

To calculate the number of moles in a given mass of a substance, we can use the formula:

`\sf \textsf{moles} = \frac{\textsf{mass}}{\textsf{molar mass}}`

For aluminum nitride (AlN), we need to know its molar mass. The molar mass is the sum of the atomic masses of all the atoms in one molecule of the compound. For aluminum nitride:

• Aluminum (Al) has a molar mass of approximately
  `\sf 27 \, \textsf{g/mol}`.
• Nitrogen (N) has a molar mass of approximately
  `\sf 14 \, \textsf{g/mol}`.

So, the molar mass of AlN is
`\sf 27 + 14 = 41 \, \textsf{g/mol}`.

Now, we can use the formula to find the number of moles:

`\sf \textsf{moles of AlN} = \frac{34.8 \, \textsf{g}}{41 \, \textsf{g/mol}}`

`\sf \textsf{moles of AlN} \approx 0.848 \, \textsf{mol}`

Therefore, there are approximately
`\sf 0.848` moles of aluminum nitride in
`\sf 34.8 \, \textsf{g}`.