Question

An arrow is shot vertically upward at a rate of 200 feet per second from ground level. Use the projectile formula h=-16t^2+v0t+h0 to determine when the height of the arrow will be 338 feet. [Recall that v0 is the intial velocity of the object and h0 is the intial height of the object.] Answer: The arrow is at 338 feet after. Round any numerical responses to two decimal places. If there are multiple answers, separate them with commas.

Answer 1

2.01 s, 10.49 s

Explanation:

h₀=0

v₀=200 ft/s

h = 338 ft

-16t² + (200 ft/s)t + 0 = 338 ft

Solve for t using quadratic formula: a = -16, b = 200, c = -338

-16t²+ 200t - 338 = 0

t = 2.01, 10.49

This means the arrow reaches a height of 338 ft after 2.01 seconds on its way up, reaches a maximum height, then falls back down to a height of 338 ft after 10.49 seconds.