Question

Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average speed of 20 miles per hour. The entire two-part, 15-mile race took him 1.125 hours to complete. Which table correctly represents his rates, times, and distances for each part of the race? A table showing Rate in mile per hour, Time in hours, and Distance in miles. The first row shows Run and has 8, t, and 8 t. The second row shows Bike, and has 20, 1.125 minus t, and 20 left-parenthesis 1.125 minus t right-parenthesis. A table showing Rate in mile per hour, Time in hours, and Distance in miles. The first row shows Run and has 8, t, and 8 t. The second row shows Bike, and has 20, 15 minus t, and 20 left-parenthesis 15 minus t right-parenthesis. A table showing Rate in mile per hour, Time in hours, and Distance in miles. The first row shows Run and has StartFraction 1 Over 8 EndFraction, t, and StartFraction 1 Over 8 EndFraction t. The second row shows Bike, and has StartFraction 1 Over 20 EndFraction, 1.125 minus t, and StartFraction 1 Over 20 EndFraction left-parenthesis 1.125 minus t right-parenthesis.

Answer 1

Not answered, but the table has been rewritten.

Explanation:

There doesn't appear to be a question associated with the problem. The table information was difficult to understand, but is reproduced below

mile per hour Time in hours Distance in miles

Run

8 t 8t

Bike

20 15-t 20(15-t)

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Run

1/8 t (1/8)t

Bike

1/20 1.125t (1/20)(1.125 - t)

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It was difficult translating the table, so check for accuracy. After arranging the table, there didn't seem to be any question as to what to do with it.