Question

A weather balloon is filled with 125.0 L helium at sea level where the pressure is 1.000 atm at 20.0 °C. After ascending until the pressure is 95.00 mmHg, the balloon expands to 750.0 L and bursts. What is the temperature (in K) at which the balloon bursts?

Answer 1

The temperature at which the balloon bursts is approximately 219.81 K.

Step-by-step explanation:

To find the temperature at which the balloon bursts, we can use the combined gas law equation:

P1V1/T1 = P2V2/T2

Given:

• P1 = 1.000 atm
• V1 = 125.0 L
• T1 = 20.0 °C + 273.15 = 293.15 K
• P2 = 95.00 mmHg = 95.00 mmHg * (1 atm / 760 mmHg) = 0.125 atm
• V2 = 750.0 L

Substituting these values into the equation, we can solve for T2:

(1.000 atm)(125.0 L)/(293.15 K) = (0.125 atm)(750.0 L)/T2

Cross multiplying and solving for T2 gives:

T2 = (0.125 atm)(750.0 L)(293.15 K)/(1.000 atm)(125.0 L)

T2 ≈ 219.81 K

Therefore, the temperature at which the balloon bursts is approximately 219.81 K.

Answer 2

220.895K

Step-by-step explanation:

T^2 = 1.000atm×125.0L/(95.00mmHg×1atm/760 mmHg)×750.0L×293.15K

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