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Slope is 1/4 and (16,4) is a point on the line

User Dyvoker
by
6.8k points

2 Answers

2 votes

Our answer is y = 1/4x.


\Large\texttt{Explanation}

We are asked to find the equation of a line, given that

⇒ the slope of this line is 1/4

⇒ the point on the line is (16,4)

Use the point-slope formula (below) to find the equation.


\bullet\quad\boldsymbol{y-y_1=m(x-x_1)}

Substitute the values


\boldsymbol{y-4=\cfrac{1}{4}(x-16)}


\boldsymbol{y-4=\cfrac{1}{4}x-4}


\boldsymbol{y=\cfrac{1}{4}x-4+4}


\boldsymbol{y=\cfrac{1}{4}x}


\therefore the equation of this line is y = 1/4x

User EnterSB
by
8.0k points
4 votes

Answer:

y =
(1)/(4) x

Explanation:

Assuming you require the equation of the line.

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given slope m =
(1)/(4) , then

y =
(1)/(4) x + c ← is the partial equation

to find c, substitute (16, 4 ) for x and y in the partial equation

4 =
(1)/(4) (16) + c = 4 + c ( subtract 4 from both sides )

0 = c

y =
(1)/(4) x ← equation of line

User Linc
by
8.2k points