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a shipment of 15 calculators contains 3 defective units. what is the probability that a sample of 3 calculators will have no defective calculators?

User Zhouji
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1 Answer

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Answer + Explanation:

The percentage of the number of defective units are:

3 : 15 = 20%

The percentage of the number of 3 calculators are:

3 : 15 = 20%

The probability that a sample of 3 calculators will have no defective calculators are:

100% - (20% x 20%) = 96%

User Goofology
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